Ask Question
8 June, 07:47

Sam is transferring files from his friend's laptop into his flash drive. This is the formula for the size of the files on Sam's friends drive S (measured in megabytes) as a function of time t (measured in seconds) : S (t) = 5t+45

Use the above information to answer the following:

When the transfer began the drive had___ megabytes of files on it

Every 10 seconds, an additional___ megabytes are transferred into the drive.

+1
Answers (1)
  1. 8 June, 11:15
    0
    1. 45 megabytes

    2. 50 megabytes

    Step-by-step explanation:

    Given

    S (t) = 5t + 45

    Required

    Find S (t) when the transfer began

    And find the additional transfer size at interval of 10 seconds

    When the file transfer initially began, the value of t is 0.

    Given that S (t) = 5t+45.

    Substitute 0 for t

    S (0) = 5 * 0 + 45

    S (0) = 0 + 45

    S (0) = 45.

    Hence, the hard drive had 45 megabytes on it when the transfer started.

    At every interval of 10 seconds. We take t to be 10, 20, 30 ... seconds

    When t = 10

    S (t) = 5t+45 becomes

    S (10) = 5 (10) + 45

    S (10) = 50 + 45

    S (10) = 95 megabytes

    When t = 20

    S (t) = 5t+45 becomes

    S (20) = 5 (20) + 45

    S (20) = 100 + 45

    S (20) = 145 megabytes

    When t = 30

    S (t) = 5t+45 becomes

    S (30) = 5 (30) + 45

    S (30) = 150 + 45

    S (30) = 195 megabytes

    Calculating the difference

    Difference = S (30) - S (20) or S (20) - S (10)

    Difference = 195 - 145 or 145 - 95

    Difference = 50 or 50

    See that the difference is the same.

    So, at every 10 seconds interval, there's an additional 50 megabytes transferred
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Sam is transferring files from his friend's laptop into his flash drive. This is the formula for the size of the files on Sam's friends ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers