Mike discovered that the pool in his backyard is leaking slowly. The pool holds 16,111 gallons of water, and is leaking at a rate of 9 gallons per day. If Mike does not replace the water that has leaked from the pool, how many gallons of water will remain in the pool after 111 days?

A.

15,612 gallons

B.

17,110 gallons

C.

16,222 gallons

D.

15,112 gallons

There are 15,112 gallons of water will remaining in the pool ⇒ answer D

Step-by-step explanation:

* Lets explain how to solve the problem

- The rate is the ratio between two related quantities in different units

- The pool is leaking slowly at rate 9 gallons per second that means the

quantity of the water in the pool decreased 9 gallons each day

- The find the remaining gallons in the pool after 111 days, find the

amount of water has leaked from the pool in these days

∵ The rate of leaking is 9 gallons per day

∵ Mike does not replace the water that has leaked from the pool

- The amount of water leaked in some days = the rate of leaking

* the number of days

∵ The number of days is 111 days

∵ The amount of water lacked = 9 * 111 = 999 gallons

∵ The amount of water remaining in the pool after some days =

the total amount in the pool - the amount of leaked in that days

∵ The pool holds 16,111 gallons of water

∴ The amount of water remaining = 16111 - 999 = 15112 gallons

* There are 15,112 gallons of water will remaining in the pool