The circumference of the inner circle is 22 ft. The distance between the inner circle

and the outer circle is 3 ft. By how many feet is the circumference of outer circle

22

greater than the circumference of the inner circle? Use 7 for it.

ft greater than the circumference of the inner circle.

The circumference of outer circle is about

(Round to the nearest tenth as needed.)

hol hornemar

18.9 ft

40.9 ft

Step-by-step explanation:

Circumference of the inner circle:

22 = 2 pi * r

22 = 2 * 22/7 * r

r = 7/2 = 3.5

Distance between the circles is the difference between the radii

Outer circle radius: 3.5 + 3 = 6.5

Circumference of the outer circle is:

2 * 22/7 * 6.5

40.85614286

To the nearest tenth: 40.9

Difference between the circumferences:

40.9 - 22

18.9 ft

Radius of outer circle = 6.5 ft

Circumference outer circle = 40.9 ft

Step-by-step explanation:

We can find the radius of the inner circle

C = 2 * pi r

22 = 2 * pi * r

22 / 2pi = 2pi r/2pi

11/pi = r

11 / (22/7) = r

3.5 = r

Add 3 to get the radius of the outer circle

The radius of the outer circle is 3+3.5 = 6.5 ft

We can find the circumference of the outer circle by

C = 2*pi*r

C = 2 * 22/7 * 6.5

C=40.85714286

Rounding to the nearest tenth

C = 40.9 ft