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25 June, 08:35

Which equation, when solved, results in a different value of x than the other 3

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  1. 25 June, 11:12
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    Let's solve this:I'm going to assume that - 7/8x and those similar are (-7/8) times x and so on. from first glance, the fourth equation looks like a failed attempt at a modifier of the first equation. Start: First equation: - (7/8) x - (3/4) = 20 multiply both sides of the equation by - 1 to make it the 2nd equation: (7/8) x + (3/4) = - (20) or to get the third equation from the first, distribute the numerator in - (7/8) x outside the parentheses (remember: top/bottom = top times 1 over bottom) : - 7 (1/8) x - (3/4) - 20equation 4 is weird (lets try to derive the first one from it) : - (7/8) (-8/7) x - (3/4) = 20 (-8/7) divide to 'get rid' of the (-8/7) - (7/8) x - (3/4) / (-8/7) = 20first and third terms are right but the second isn't; therefore, the 4th equation is the different one
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