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8 November, 00:01

Una ambulancia se desplaza hacia el norte. A 23, 5 m/s. Su sirena emite un sonido de 500 hz de frecuencia. Calcular la frecuencia aparente que percibe. Un observador. Que viaja en su auto, también hacia el norte. A 18, 6 m/s cuando : el auto se aleja de la ambulancia

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  1. 8 November, 00:55
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    The apparent frquency would be

    f' = 493.26 Hz

    Step-by-step explanation:

    This a Doppler's effect problem. This effects produces a slight change in the frequency of a traveling wave, due to the effect of the velocity of the receiver (observer).

    The formula used to describe the change, as both vehicles are moving away of each other:

    f' = [ (Vwave + Vobserver) / (Vwave + Vsource) ]*f

    Where

    Vwave = 340 m/s (speed of sound)

    Vobserver = 18.6 m/s (observer = car)

    Vsource = 23.5 m/s (speed of the ambulance = source)

    f = 500 Hz (frequency of the sound)

    We just need to substitute in the equation

    f' = [ (340 + 18.6) / (340 + 23.5) ] * 500 Hz

    f' = [0.9865] * 500 Hz = 493.26 Hz

    f' = 493.26 Hz
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