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29 November, 06:52

If f (x) = x/3-2then find g (x) = 3x^2+2x-6

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  1. 29 November, 07:48
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    Step-by-step explanation:

    Answer:

    (f+g) (x) = 3x^2+/frac{7}{3}x-8

    Step-by-step explanation:

    The given functions are:

    f (x) = / frac{x}{3}-2 and g (x) = 3x^2+2x-6

    Now, (f+g) (x) = f (x) + g (x)

    therefore, (f+g) (x) = / frac{x}{3}-2+3x^2+2x-6

    =3x^2+2x+/frac{x}{3}-8

    =/frac{9x^2+6x+x-24}{3}

    =/frac{9x^2+7x-24}{3}

    =3x^2+/frac{7}{3}x-8

    Thus, (f+g) (x) = 3x^2+/frac{7}{3}x-8
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