Ask Question
18 June, 21:10

You have 9 chairs arranged in a circle, and wish to seat 9 people (one person per seat). The one constraint is that person A cannot sit next to person B or person C (three of the people). How many ways are there to seat them?

+1
Answers (1)
  1. 18 June, 23:40
    0
    30240 number of ways are there to seat them

    Step-by-step explanation:

    Total number of ways of arranging 9 people on 9 chairs in circular manners = (9-1) ! = 8! =

    number of ways A sit always sit next to B = AB together makes a single and

    therefore total number of arrangements for this = 7 + (AB) = 8 that is 8 persons sitting in circular manner

    number of ways = (8-1) ! = 7! = 5040

    likewise number of arrangements for A and C will be = 5040

    Total number of ways such that A cannot sit next to B or C = total ways of 9 persons - total number of A always sitting next to B - total number of ways always sitting next to C = 8! - 7!-7!

    = 40320 - 5040-5040

    = 30240

    =
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “You have 9 chairs arranged in a circle, and wish to seat 9 people (one person per seat). The one constraint is that person A cannot sit ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers