Use the quadratic formula to determine the solutions to the quadratic equation. Write your answers as decimals, and round to the nearest hundredth (2 decimal spots).

6x2+4x-3=0

Either x≈ - 1.12 or x ≈0.45

Step-by-step explanation:

Using the quadratic formula to solve this, we will follow the steps below;

First, write down the quadratic formula;

x = - b ±√b² - 4ac / 2a

From the question, the equation given is: 6x²+4x-3=0

comparing the equation given withe standard equation ax² + bx + c=0

a = 6 b = 4 and c = - 3

We can now proceed to insert the values into the formula;

x = - 4 ±√4² - 4 (6) (-3) / 2 (6)

x = - 4 ±√16+72 / 12

x = - 4 ±√88 / 12

Either x = - 4+√88 / 12

x ≈0.45

OR

x = - 4 - √88 / 12

x≈ - 1.12

Either x≈ - 1.12 or x ≈0.45

x1 = 0.45 and x2 = - 1.12

Step-by-step explanation:

To solve the equation 6x2+4x-3=0 using the quadratic formula, we use the following equation:

x = [-b ± √ (b2 - 4ac) ] / 2a

Where a, b and c are coefficients of the quadratic equantion (in our case, a = 6, b = 4 and c = - 3)

So we have that:

x1 = [-4 + √ (16 + 72) ] / 12 = (-4 + 9.3808) / 12 = 0.4484

x2 = [-4 - √ (16 + 72) ] / 12 = (-4 - 9.3808) / 12 = - 1.1151

Rounding to nearest hundredth, we have x1 = 0.45 and x2 = - 1.12