The graph above represents the following polynomial function.

f (x) = x^3 - 2x^2 - 3x

What are the solutions to the function?

A.

x = - 3, x = - 1, and x = 0

B.

x = - 3, x = 0, and x = 1

C.

x = - 1, x = 0, and x = 3

D.

x = 0, x = 1, and x = 3

C. 0, - 1, 3

Step-by-step explanation:

Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".

x (x^2-2x-3) = 0

/ (x^2-2x-3)

x=0

x^2-2x-3 = x^2+x-3x-3 = x (x+1) + (-3 (x+1) = (x-3) (x+1)

/ (x-3) - -> x + 1 = 0, x=-1

/ (x+1) - -> x-3 = 0, x=3