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18 January, 23:27

Tom throws a Frisbee into the air from a height of 4 feet with

an initial vertical velocity of 64 feet per second. Use the vertical

motion model, h = - 16t2 + vt + s, where v is the initial velocity in

feet/second and s is the height in feet, to calculate the

maximum height of the frisbee. Round your answer to the

nearest tenth if necessary.

Maximum height: - feet

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Answers (1)
  1. 19 January, 03:19
    0
    68 feet

    Step-by-step explanation:

    Vertical motion model:

    h = - 16t² + vt + s

    Given v = 64 and s = 4:

    h = - 16t² + 64t + 4

    This is a parabola. The maximum of a parabola is at the vertex.

    For y = ax² + bx + c, the vertex is at x = - b / (2a).

    Therefore, the time to reach the maximum height is:

    t = - 64 / (2 * - 16)

    t = 2

    And the maximum height is:

    h = - 16 (2) ² + 64 (2) + 4

    h = 68

    So the Frisbee reaches a maximum height of 68 feet.
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