Identify the axis of symmetry for the following equation:

y = x^2 + 10x + 26

A) x = - 5

B) x = 2

The answer to your question is the letter A.

Step-by-step explanation:

Data

y = x² + 10x + 26

Factor the right side of the equation

y - 26 = x² + 10x

-Complete the perfect trinomial square

y - 26 + (5) ² = x² + 10x + (5) ²

-Simplify

y - 26 + 25 = x² + 10x + 25

y - 1 = (x + 5) ²

Vertex = (-5, 1)

The function given is a vertical parabola whose axis of symmetry goes through x = - 5

(-5) ... hope it's right