Write thw equation of the line that it is perpendicular to y=7x-3 and passes through the origin

Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0

Explanation:

We have equation of line, y = 7x - 3, comparing it with y = mx + c

So slope of line, m = 7

We know that the product of slopes of perpendicular lines = - 1

So m*Slope of perpendicular line = - 1

7 * slope of perpendicular line = - 1

slope of perpendicular line = - 1/7

Given that the perpendicular line passes through origin (0,) 0)

We also know that equation of a line passing though origin is given by the expression, y = mx

Here m = - 1/7

So equation of perpendicular line, y = - x/7

or 7y + x = 0

Equation of the line that it is perpendicular to y=7x-3 and passes through the origin is given by 7y + x = 0