A bag contains 6 red balls numbered 1, 2, 4, 5, 8, 9 and 4 white balls numbered 3, 6, 7, 10,

at random, what is the probability the ball is

8, 9 and 4 white balls numbered 3, 6, 7, 10. If a ball is drawn

a. red or odd-numbered?

b. white or even-numbered

60%

a. 80%

b. 70%

Step-by-step explanation:

In this case we are first asked for the probability that when drawing a ball at random it is 8, 9 and 4 white balls numbered 3, 6, 7, 10, that is 6 balls. We know that there are a total of 10 balls since they are 6 red and 4 white, 6 + 4 = 10.

Therefore the probability is:

6/10 = 0.6

that is to say that the probability that it is one of these balls is 60%

to. that is red or odd,

red are 1, 2, 4, 5, 8, 9 and in addition to that, in white there is one with 3 and with 7 that are odd, making them 8 balls, therefore:

8/10 = 0.8

In other words, the probability is 80%

b. white or even,

the white ones are 3, 6, 7, 10 and in the red ones the 2, 4 and 8 are even, that is to say that they are 7 balls, which means that:

the probability is:

7/10 = 0.7

The probability is 70%