Identify the vertex for the graph of y = - 3x^2 + 6x - 4

(1, 5)

(1, - 1)

(-1, - 13)

(-1, - 9)

the vertex is (1,-1)

Step-by-step explanation:

y = - 3x^2 + 6x - 4

the vertex is at

h = - b/2a where ax^2 + bx+c

h = - 6/2 (-3)

h = - 6/-6

h=1

substitute this in to find the y value

y = - 3 (1) ^2 + 6 (1) - 4

y = - 3+6-4

y = - 1

the vertex is (1,-1)