What is the slope of a line perpendicular to the line with equation 5x+3y=7

3/5

Step-by-step explanation:

5x+3y=7

First we need to solve for the slope by finding y

Subtract 5x from each side

5x-5x+3y=-5x+7

3y = - 5x+7

Divide by 3

3y/3 = - 5x/3 + 7/3

y = - 5/3 x + 7/3

This is in slope intercept form so we can see the slope is - 5/3

We want a line that is perpendicular

That is the negative reciprocal

m perpendicular = - (-3/5)

= 3/5