If 60 metres of fencing was available to make a rectangular pen with length, L, and width, W, then the formula for the area, A, of the pen is given by:

1. A = (30-L) W

2. A = (30-W) W

3. A = (30-W) L

4. A = (60-2L) W

5. A = (60-2W) L

Question

Mathematics

Guest

25 November, 17:39

If 60 metres of fencing was available to make a rectangular pen with length, L, and width, W, then the formula for the area, A, of the pen is given by:

1. A = (30-L) W

2. A = (30-W) W

3. A = (30-W) L

4. A = (60-2L) W

5. A = (60-2W) L

+3

Answers (1)

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Azkaban · Answer 1

2. (30-W) * W

Step-by-step explanation:

In order to find the answer we need the formula for the area of a rectangle, which is:

area = (length) * (width) which is:

A=L*W

Now, beacuse 60 meters of fencing were used, this means that 60 meters is the perimeter of the rectangle, so:

perimeter = (2*length) + (2*width) which is:

60=2L+2W

30=L+W which can be written as:

30-W=L

Using the area's formula we have:

A=L*W which, using the previous expression, can be written as:

A = (30-W) * W

In conclusion, the answer is 2. (30-W) * W.

If 60 metres of fencing was available to make a rectangular pen with length, L, and width, W, then the formula for the area, A, of the pen is given by:1. A = (30-L) W2. A = (30-W) W3. A = (30-W) L4. A = (60-2L) W5. A = (60-2W) L

If 60 metres of fencing was available to make a rectangular pen with length, L, and width, W, then the formula for the area, A, of the pen is given by:

1. A = (30-L) W

2. A = (30-W) W

3. A = (30-W) L

4. A = (60-2L) W

5. A = (60-2W) L