Ask Question
14 January, 17:46

The quadratic polynomial x^2 + mx+n has roots twice those of x^2 + px+m, and none of m, n, and p is zero. What is the value of n/p?

Answers (1)
  1. D
    14 January, 20:52
    0
    n/p = 8.

    Step-by-step explanation:

    If the roots of the first equation are A and B we have

    A + B = - m and AB = n.

    This has roots twice the roots of the second equation so we have:

    0.5 (A + B) = - p and 0.25AB = m.

    So A + B = - 2p and AB = 4m

    Equating values of A + B and AB:

    -m = - 2p and n = 4m

    m = 2p and m = n/4

    2p = n/4

    n = 8p

    n/p = 8.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “The quadratic polynomial x^2 + mx+n has roots twice those of x^2 + px+m, and none of m, n, and p is zero. What is the value of n/p? ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers
Sign In
Ask Question