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16 July, 18:35

a local Library Bar 54 books some cost $32 each and some cost $44 each the total cost of the books was $1,968 how many of the $32 books were purchased

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  1. 16 July, 20:58
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    To solve this, we'll first need to set it as a system of equations.

    First, let's let

    x = No. of $32 books purchased.

    y = No. of $44 books purchased.

    We know that 54 books were sold in total and they the total cost of the books sold were 1968. Using this information we can come up with two equations.

    x + y = 54

    32x + 44y = 1968

    We will solve this system by the substitution method. Solve the first equation for y.

    y = - x + 54

    Substitute this for y in your second equation.

    32x + 44 (-x + 54) = 1968

    Distribute and add like terms.

    -12x + 2376 = 1968

    Solve for x.

    x = 34.

    Your answer should be: 34 $32 books were purchased.
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