Find either the maximum or the minimum value of the following quadratic equation. Be sure to show all of your work and identify the maximum or minimum value correctly.

y = 5x^2 - 10x - 4

the minimum is (1,-9)

Step-by-step explanation:

y = 5x^2 - 10x - 4

since the parabola opens upward 5>0, this will have a minimum

it will occur along the axis of symmetry h=-b/2a

y = ax^2 + bx+c

h = - (-10) / 2*5

h = 10/10 = 1

the minimum occurs at x = 1

the y value for the minimum is calculated by substituting x = 1 back into the equation

y = 5 * 1^2 - 10*1 - 4

y = 5*1^2 - 10 - 4

y = 5-10-4

y = - 9

the minimum is (1,-9)