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24 January, 01:07

Solve the equation and express each solution in a+bi form. 7x^2+18=0

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  1. 24 January, 02:34
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    x = 0 ±3/7 i sqrt (14)

    Step-by-step explanation:

    7x^2 + 18 = 0

    subtract 18 from each side

    7x^2 = - 18

    divide by 7

    x^2 = - 18/7

    take the square root of each side

    sqrt (x^2) = ±sqrt (-18/7)

    sqrt (x^2) = ±sqrt (-1) sqrt (18/7)

    sqrt (-1) = i

    x = ±isqrt (18/7)

    x = ±isqrt (18) / sqrt (7)

    x = ±isqrt (9) sqrt (2) / sqrt (7)

    x = ±3i sqrt (2) / sqrt (7)

    cannot leave a sqrt in the denominator

    x = ±3i sqrt (2) * sqrt (7) / (sqrt (7) * sqrt (7))

    x = ±3i sqrt (14) / 7

    x = ±3/7 i sqrt (14)
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