The slope, m, of a linear equation can be found using the formula m = StartFraction y 2 minus y a Over x 2 minus x 1 EndFraction., where the x - and y-values come from two ordered pairs, and (x1, y1) and (x2, y2).

What is an equivalent equation solved for y2?

y2 = m (x2-x1) + y1

Step-by-step explanation:

Given the formula for finding the slope of a linear equation to be;

m = y2-y1/x2-x1 where x and y are from the ordered pairs (x1, y1) and (x2, y2)

To get the equivalent equation for y2, we will make y2 the subject of tbw formula from the equation as shown:

m = y2-y1/x2-x1

Cross multiplying

m (x2-x1) = y2-y1

mx2-mx1 = y2-y1

Adding y1 to both sides of the equation we have;

mx2-mx1 + y1 = y2-y1+y1

y2 = mx2-mx1 + y1

y2 = m (x2-x1) + y1

This gives the resulting equation to solve for y2