What is the area of a triangle whose vertices are D (3, 3), E (3, - 1), and F (-2, - 5) What is the area of the rectangle?

The area of the triangle with the given vertices is 10 square units

Step-by-step explanation:

x y

D 3 3

E 3 - 1

F - 2 - 5

D 3 3

Area: A=Abs [ (xd ye + xe yf + xf yd) - (yd xe + ye xf + yf xd) ] / 2

Absolute value: Abs

A = Abs { [ (3) (-1) + (3) (-5) + (-2) (3) ] - [ (3) (3) + (-1) (-2) + (-5) (3) ] } / 2

A = Abs [ (-3-15-6) - (9+2-15) ] / 2

A = Abs [ (-24) - (-4) ] / 2

A = Abs (-24+4) / 2

A = Abs (-20) / 2

A = 20 / 2

A = 10 square units