Which equation, when solved, results in a different value of x than the other three?

-7/8x-3/4=20

3/4+7/8x=-20

-7 (1/8) x-3/4=20

-7/8 (-8/7) x-3/4=20 (-8/7)

Let's solve this:

I'm going to assume that - 7/8x and those similar are (-7/8) times x and so on.

from first glance, the fourth equation looks like a failed attempt at a modifier of the first equation.

Start: First equation:

- (7/8) x - (3/4) = 20

multiply both sides of the equation by - 1 to make it the 2nd equation:

(7/8) x + (3/4) = - (20)

or to get the third equation from the first, distribute the numerator in - (7/8) x outside the parentheses (remember: top/bottom = top times 1 over bottom):

- 7 (1/8) x - (3/4) - 20

equation 4 is weird (lets try to derive the first one from it):

- (7/8) (-8/7) x - (3/4) = 20 (-8/7)

divide to 'get rid' of the (-8/7)

- (7/8) x - (3/4) / (-8/7) = 20

first and third terms are right but the second isn't; therefore, the 4th equation is the different one