3n^2-2n-8 Factoring trinomials II

(3n + 4) (n-2)

Step-by-step explanation:

Are you asking to factor this 3n^2 - 2n - 8?

If so the best way to do this problem is with the X method.

top: 3 * (-8)

left: factor of 3*-8 right: factor of 3*-8

bottom: - 2

try the factors 4 and - 6 because 4*-6 = 3 * -8 = - 24

Because notice that 4 + - 6 = - 2

so:

3n^2 - 2n - 8 can be rewritten as 3n^2 - 6n + 4n - 8

We should first use Distributive property to factor: 3n^2 - 6n + 4n - 8

3n^2 - 6n + 4n - 8 = 3n (n - 2) + 4 (n - 2)

Now we factor by grouping here : (3n + 4) (n-2)

I factored out the group (n-2)

Therefore: (3n + 4) (n-2) = 3n^2 - 2n - 8