Compute the permutations and combinations. A company has 10 men qualified to run a machine that requires 3 operators at a time. Find how many groups of 3 operators are possible. 240 720 120

120

Step-by-step explanation:

To solve this question we would be using combination formula.

The formula for combination is given as:

C (n, r) = nCr

nCr = n!/r! * (n - r) !

In the above question,

n = 10 men

r = 3 operators

Hence,

nCr = n!/r! * (n - r) !

10C3 = 10! / 3! * (10 - 3) !

10C3 = 10!/3! * 7!

10C3 = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 / (3 * 2 * 1) * (7 * 6 * 5 * 4 * 3 * 2 * 1)

10C3 = 10 * 9 * 8 / 3 * 2 * 1

10C3 = 720/6

10C3 = 120

Therefore, the number of groups of 3 operators that are possible is 120.