The angle 01 is located in Quadrant II, and sin (01) =

9/41

What is the value of cos (01) ?

Express your answer exactly.

cos (01) =

-40/41

Step-by-step explanation:

Since we know 'cos' involves the Adjacent and Hypoteneus sides, we will need to solve for the 'Adjacent' side of the triangle using the Hypoteneus Theorem.

41² = 9² + a²

a = 40.

However, this is in quadrant II, so when finding the 'cos' value, this side is - 40.

Cosine is A/H, giving is:

cos (01) = - 40/41