Ask Question
22 December, 00:51

Solve the old 2x+log12=3 round to the nearest hundredth if necessary

6,000

24,000

166.67

41.67

+5
Answers (1)
  1. 22 December, 01:40
    0
    41.67

    Step-by-step explanation:

    log 2x+log12=3

    log (a) + log (b) = log (ab)

    log (2x*12) = 3

    log (24x) = 3

    raise each side to the power of 10

    10 ^ log (24x) = 10 ^3

    24x = 1000

    divide by 24

    24x/24 = 1000/24

    x = 41.666666666 ...

    rounding to the nearest hundredth

    41.67
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Solve the old 2x+log12=3 round to the nearest hundredth if necessary 6,000 24,000 166.67 41.67 ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers