What is the solution to the system of equations below?

2 x minus y = 10 and y = negative one-half x + 5

(6, 2)

(6, - 2)

(-6, - 22)

(-6, 8)

The correct one is A

Step-by-step explanation:

2x-y=10

y=1/2 * x+5

Now you substitute the value of y into the first equation.

2x - (1/2 * x+5) = 10

Solving this equation for x you get that x=6

Now substitute the value of x any of these two equations, doesn't matter. Let's say we do with the first one.

2*6-y=10

12-y=10

-y=10-12

-y = - 2

y=2

And so you've got the first one which is, (x, y) = (6,2)

the correct answer is a