In △ABC, c=28, m∠B=92°, and a=38. Find b.

=48.0

Step-by-step explanation:

In this problem we can use the cosine formula to find b.

b²=a²+c²-2acCosB

Where a, b and c are the sides of the triangle.

Substituting with the values from the question gives:

b²=28²+28²-2*38*28*Cos 92

b²=2302.26

b=√2302.26

=47.98

The side b=48.0 to the nearest tenth.