A train leaves Roseville heading east at 6:00 am at 40 miles per hour. Another eastbound train leaves on a parallel track at 7:00 am at 50 miles per hour. What times will it be when the two trains are at the same distance away from Roseville?

At 11:00 am the both trains will be at same distance away from Roseville

Step-by-step explanation:

The first train was 40 miles away from Roseville at 7:00 am

After some time t the both trains will be at the same distance away from Roseville.

We will make equation for that situation

d - distance v1 = 40mph and v2 = 50mph - velocity

d = v1*t + 40 = v2*t = > v2*t - v1*t = 40 = > t (v2-v1) = 40 - > t = 40 / (v2-v1)

t = 40 / (50-40) = 40/10 = 4h t = 4h

7:00 am * 4h = 11:00 am

Good luck!