consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p (b) = 0.3

Question

Mathematics

Koty

19 May, 11:52

consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p (b) = 0.3

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Brian Russo · Answer 1

P (B) = 0.30

Step-by-step explanation:

Out of 1000 Voters, 30% favor Jones.

Event S=Favors Jones on First Trial

Event B=S occurs on Second Trial

P (S) = 0.30

P (S') = 1-0.30=0.70

Event B could occur in two ways

The first two trials are a success The first trial is a failure and the second trial is a success.

Therefore,

P (B) = P (SS) + P (S'S)

= (0.3X0.3) + (0.7X0.3)

=0.09+0.21

=0.3

Therefore, the probability of event B (that event S occurs on the second trial), P (B) = 0.30.