Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.

Tony has $20. He wants to buy at least 4

snacks. Hot dogs (x) are $3 each.

Peanuts (y) are $2 each.

Answer:

To solve the above question, we use the below inequality equations

x + y ≥ 4 snacks ... Inequality equation 1

3x + 2y ≤ $20 ... Inequality equation 2

Step-by-step explanation:

We can make use of the inequality equations

Hot dogs = (x) are $3 each.

Peanuts = (y) are $2 each.

He wants to buy at least 4

x + y ≥ 4 snacks ... Inequality equation 1

3x + 2y ≤ $20 ... Inequality equation 2

From the above inequality equations, Tony can buy at least 4 snacks but he can only spend $20.

Let take a random number, where x = 4, and y = 4. This means Tony can buy

a) 4 ($3) + 4 ($2) = 12 + 8 = $20

The total number of snacks = 4 + 4 = 8 snacks.

b)

This answer above confirms the inequality equations 1 and 2

x + y ≥ 4 snacks ... Inequality equation 1

8 snacks ≥ 4 snacks

3x + 2y ≤ $20 ... Inequality equation 2

$20 ≤ $20