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19 April, 02:40

Solve each quadratic equation by factoring and using the zero product property.

14x - 49 = x^2

+1
Answers (2)
  1. 19 April, 04:37
    0
    x = 7

    Step-by-step explanation:

    Given equation is:

    14x-49 = x²

    adding - x² to both sides of equation, we get

    -x²+14x-49 = - x²+x²

    -x²+14x+49 = 0

    take - 1 as common

    -1 (x²-14x-49) = 0

    now multiplying above equation to - 1, we get

    x²-14x-49 = 0

    Now, above equation is in general equation.

    split the middle term of above equation so that the product of two terms should be 49 and sum be - 14.

    x²-7x-7x-49 = 0

    make two groups

    x (x-7) - 7 (x-7) = 0

    take (x-7) as common

    (x-7) (x-7) = 0

    Now applying Zero-Product Property to above equation, we get

    x-7 = 0 or x-7 = 0

    as both are same, hence

    x-7 = 0

    adding 7 to both sides of above equation, we get

    x-7+7 = 0+7

    x+0 = 7

    x = 7 which is the answer.
  2. 19 April, 04:57
    0
    x=7 multiplicity of 2

    Step-by-step explanation:

    14x - 49 = x^2

    Subtract x^2 from each side

    -x^2 + 14x - 49 = x^2-x^2

    -x^2 + 14x - 49 = 0

    Multiply by - 1

    x^2 - 14x + 49 = 0

    What 2 numbers multiply together to give you 49 and add together to give you - 14

    7*-7 = 49

    -7+-7 = - 14

    (x-7) (x-7) = 0

    Using the zero product property

    x-7 = 0 x-7 = 0

    x-7+7 = 0+7 x-7+7 = 0+7

    x = 7 x=7
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