Huong's school is selling tickets to a fall musical. On the first day of ticket sales the school sold 11 adult tickets and 3 student tickets for a total of $110. The school took in $87 on the second day by selling 3 adult tickets and 6 student tickets. What is the price each of one adult ticket and one student ticket?

11a + 3s = 110

3a + 6s = 87

-22a - 6s = - 220

3a + 6s = 87

-19a = - 133

a = $7 adult ticket

3 (7) + 6s = 87

21 + 6s = 87

6s = 66

s = $11 student ticket

Adult ticket: $7 Student ticket: $11

Step-by-step explanation:

First, we set up our equations.

x (adult ticket) y (student ticket)

For the first day, 11x + 3y = 110

For the second day, 3x + 6y = 87

Then we solve.

(-2) 11x + 3y = 110

Equals

-22x - 6y = - 220

Add them

-22x - 6y = - 220

3x + 6y = 87

This equals

-19x = - 133

x = 7

Plug in to find y

3 (7) + 6y = 87

21 + 6y = 87

6y = 66

y = 11