If z is a standard normal variable, find the probability that z lies between 0.7 and 1.98.

P (Z₁ < z < Z₂) = A (Z₂) - A (Z₁) = 0.2182

Step-by-step explanation:

Given Z is a standard normal variable

Given Z₁ = 0.7 and Z₂ = 1.98

P (Z₁ < z < Z₂) = P (0.7 < z < 1.98)

Here Z₁ and Z₂ both are positive

P (Z₁ < z < Z₂) = A (Z₂) - A (Z₁)

= A (1.98) - A (0.7)

= 0.4762 - 0.2580

= 0.2182

Conclusion:-

P (Z₁ < z < Z₂) = A (Z₂) - A (Z₁) = 0.2182