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12 September, 08:27

H (x) = - 5x2 + 10x + 15

What is the height of the stone at the time it is thrown?

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  1. 12 September, 10:15
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    The height of the stone at the time it is thrown is 15.

    Step-by-step explanation:

    You have a quadratic function of the form h (x) = ax² + bx + c. In this case it is h (x) = - 5x²+10x+15, where a = -5, b = 10, c = 15, x is the time and h (x) is the height of the stone after being thrown.

    The moment the stone is thrown is instant zero. So if x = 0, h (0) is calculated:

    h (0) = - 5*0² + 10*0 + 15

    h (0) = 0 + 0 + 15

    h (0) = 15

    The height of the stone at the time it is thrown is 15.
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