if the diameter of a nickel is 0.835 in and the width of each nickel is 0.077 in what is the approximate surface area of the 2$ roll of nickels round your answer to the nearest hundredth

Step-by-step explanation:

The roll of nickels forms a cylinder

cylinder area includes the sides and the round areas

round areas = pi r^2 there is two so 2 pi r^2

= 2 pi (.835/2) ^2

and the side area pi x d x h

pi x. 835 (.077 x 40) (there are 40 nickels in $ 2

Add the areas to get the total ...