He function f (x) = x^2 + 10x - 3 written in vertex form is fx) = (x+5) ^2 - 28. What are the coordinates of the vertex?

0 (-5, - 28)

O (-5, 28)

O (5.-28)

O (5, 28)

Question

Mathematics

Superman

28 July, 22:56

He function f (x) = x^2 + 10x - 3 written in vertex form is fx) = (x+5) ^2 - 28. What are the coordinates of the vertex?

0 (-5, - 28)

O (-5, 28)

O (5.-28)

O (5, 28)

+1

Answers (1)

Know the Answer?

Johanna Mcknight · Answer 1

( - 5, - 28)

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a (x - h) ² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

f (x) = (x + 5) ² - 28 ← is in vertex form

with vertex (h, k) = ( - 5, - 28)

He function f (x) = x^2 + 10x - 3 written in vertex form is fx) = (x+5) ^2 - 28. What are the coordinates of the vertex?0 (-5, - 28)O (-5, 28)O (5.-28)O (5, 28)

He function f (x) = x^2 + 10x - 3 written in vertex form is fx) = (x+5) ^2 - 28. What are the coordinates of the vertex?

0 (-5, - 28)

O (-5, 28)

O (5.-28)

O (5, 28)