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17 May, 01:34

a caj register contains $10 and $50 with a total value of$1080. If there are 28 bills total, then how many if each does the register contain?

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  1. 17 May, 04:33
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    Step-by-step explanation:

    We can solve by means of a system of equations:

    let x register $ 10

    let y register $ 50

    Now, we have:

    10 * x + 50 * y = 1080

    x + y = 28 = >
    replacing:

    10 * (28 - y) + 50 * y = 1080

    280 - 10 * y + 50 * y = 1080

    40 * y = 1080 - 280

    y = 800/40

    y = 20

    now for x:

    x = 28 - 20

    x = 8

    which means that in total there are 8 register of $ 10 and 20 register of $ 50
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