Ask Question
30 December, 20:37

A car puchased for $12,000 depreciates under a straight-line method in the amount of $850 each year. Which equation below best models this depreciation?

A) y = 12000x + 850

B) y = 12000 + 850x

C) y = 12000x - 850

D) y = 12000 - 850x

+4
Answers (2)
  1. 30 December, 21:58
    0
    D) y = 12000 - 850x

    Step-by-step explanation:

    Given that the car is purchased for an initial value of $12,000 and depreciates each year at the same rate, you can set 'x' equal to the amount of time in years and - $850 for the rate at which it declines in price each year. If 'y' represents the total value of the car, than after so many years 'x', at a rate of - $850 per year, then the best model for this scenario is:

    y = 12000 - 850x
  2. 30 December, 23:38
    0
    Answer D: y = $12,000 - ($850/year) x (Answer D)

    Step-by-step explanation:

    In all cases the value of the car begins at $12,000. From this we subtract $850 in depreciation each year.

    Thus, after one year, the value of the car is $12,000 - $850, or $11,150.

    After x years, the value is $12,000 - ($850/year) x (Answer D)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A car puchased for $12,000 depreciates under a straight-line method in the amount of $850 each year. Which equation below best models this ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers