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21 September, 15:03

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

0 = 2x2 - 4x + 1

0 = 2x2 - 5x + 3

0 = - 2x2 - 4x - 2

0 = - 2x2 - 3x - 1

+2
Answers (2)
  1. 21 September, 15:25
    0
    We know that a quadratic has one real number solution just than the discriminant is equal zero

    so in case of 3rd equation

    0 = - 2x^2 - 4x - 2 = > D = 16 - 16 = 0
  2. 21 September, 16:15
    0
    It is C ...
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