What are the zeros of 2x^2-6x-8

x=4 x=-1

Step-by-step explanation:

2x^2-6x-8

Factor out a 2

2 (x^2 - 3x-4)

What 2 numbers multiply to - 4 and add to - 3

-4 * 1 = - 4

-4+1 = - 3

2 (x-4) (x+1)

Set this equal to zero to find the zero's

2 (x-4) (x+1) = 0

Using the zero product property

x-4 = 0 x+1 = 0

x=4 x=-1