Ask Question
11 March, 05:53

What is the product of the expressions? Assume y ≠ 0. (2y-1/y2) (3y2/7)

+1
Answers (1)
  1. 11 March, 08:08
    0
    (2y-1/y_2) (3y_2/7)

    = 2y * (3y_2/7) - (1/y_2) (3y_2/7)

    = 6y*y_2/7 - 3/7 = (6y*y_2 - 3) / 7

    Note: I'm not sure if the 2y-1 was written correctly. If it were intended as the entire thing being a numerator or as 2y_1, this answer is inaccurate.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “What is the product of the expressions? Assume y ≠ 0. (2y-1/y2) (3y2/7) ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers