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22 January, 14:56

6. (08.04)

What is the sum of the geometric sequence 2, 8, 32, ... if there are 8 terms?

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  1. 22 January, 16:47
    0
    43,690.

    Step-by-step explanation:

    The common ratio r is 8/2 = 32/8 = 4.

    Sum of n terms = a1 * (r^n - 1) / (r - 1).

    a1 = 2 and r = 4 so

    Sum of 8 terms = 2 * (4^8 - 1) / (4 - 1)

    = 2 * 65535 / 3

    = 43,690.
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