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28 January, 08:29

The ages of students in a school are normally distributed with a mean of 16 years and a standard deviation of 1 year. Using the empirical rule, approximately what percent of the students are between 14 and 18 years old?

32%

68%

95%

99.7%

(i know its not B)

+4
Answers (2)
  1. 28 January, 11:04
    0
    The percent of the students between 14 and 18 years old is 95% ⇒ answer C

    Step-by-step explanation:

    * Lets revise the empirical rule

    - The Empirical Rule states that almost all data lies within 3

    standard deviations of the mean for a normal distribution.

    - 68% of the data falls within one standard deviation.

    - 95% of the data lies within two standard deviations.

    - 99.7% of the data lies Within three standard deviations

    - The empirical rule shows that

    # 68% falls within the first standard deviation (µ ± σ)

    # 95% within the first two standard deviations (µ ± 2σ)

    # 99.7% within the first three standard deviations (µ ± 3σ).

    * Lets solve the problem

    - The ages of students in a school are normally distributed with

    a mean of 16 years

    ∴ μ = 16

    - The standard deviation is 1 year

    ∴ σ = 1

    - One standard deviation (µ ± σ):

    ∵ (16 - 1) = 15

    ∵ (16 + 1) = 17

    - Two standard deviations (µ ± 2σ):

    ∵ (16 - 2*1) = (16 - 2) = 14

    ∵ (16 + 2*1) = (16 + 2) = 18

    - Three standard deviations (µ ± 3σ):

    ∵ (16 - 3*1) = (16 - 3) = 13

    ∵ (16 + 3*1) = (16 + 3) = 19

    - We need to find the percent of the students between 14 and 18

    years old

    ∴ The empirical rule shows that 95% of the distribution lies

    within two standard deviation in this case, from 14 to 18

    years old

    * The percent of the students between 14 and 18 years old

    is 95%
  2. 28 January, 11:47
    0
    Answer Choice C is correct - 95%
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