Ask Question
2 June, 18:30

6x + 1 = 2 (3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions

+2
Answers (2)
  1. 2 June, 20:28
    0
    D) infinitely many solutions

    Step-by-step explanation:

    6x + 1 = 2 (3x - 2) + 5

    Distribute

    6x+1 = 6x - 4+5

    Combine like terms

    6x+1 = 6x+1

    Subtract 6x from each side

    6x-6x+1 = 6x-6x+1

    1=1

    This is always true, so x has infinite solutions
  2. 2 June, 20:46
    0
    6x + 1 = 2 (3x - 2) + 5

    6x + 1 = 6x - 4 + 5

    6x + 1 = 6x + 1

    6x = 6x

    x = x

    D.) Infinitely many solutions
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “6x + 1 = 2 (3x - 2) + 5 A) x = 0 B) x = 12 C) x = 1 12 D) infinitely many solutions ...” in 📘 Mathematics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers