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4 November, 12:12

Solve: 18^x^2+4x+4 = 18^9x+18

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  1. 4 November, 13:02
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    x = - 2 or + 7

    Step-by-step explanation:

    We presume you want to solve ...

    18^ (x^2 + 4x + 4) = 18^ (9x + 18)

    Equate exponents of the same base and put the quadratic in standard form.

    x^2 + 4x + 4 = 9x + 18

    x^2 - 5x - 14 = 0

    (x - 7) (x + 2) = 0

    Values of x that make these factors zero are 7 and - 2.

    The solutions are x=-2 or x = 7.
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