In a certain Algebra 2 class of 30 students, 18 of them play basketball and 9 of them

play baseball. There are 10 students who play neither sport. What is the probability

that a student chosen randomly from the class plays both basketball and baseball?

Probability that a student will play both is 7/30

Step-by-step explanation:

Total students = 30

No. of students who play basketball = 18

Probability that a student will play basketball = 18/30

= 3/5

No. of students who play baseball = 9

Probability that a student will play baseball = 9/30

= 3/10

No. of students who play neither sport = 10

Probability that a student will play neither sport = 10/30

= 1/3

To find:

Probability that a student will play both = p (student will play both)

No. of students who play sport = 30 - 10

= 20

Out of 20 students 18 play basketball and 9 play baseball.

So, some students play both the sports.

No. of students who play both sports = 18 + 9 - 20

= 7

p (student will play both) = 7/30

Probability that a student will play both is 7/30