A football quarterback enjoys practicing his long passes over 40 yards. He misses the first pass 40% of the time. When he misses on the first pass, he misses the second pass 20% of the time. What is the probability of missing two passes in a row?

Probability of missing two passes in a row is 0.08.

Step-by-step explanation:

Event E = A football player misses twice in a row.

P (E) = ?

Event X = Football player misses the first pass

P (X) = 0.4

Event Y = Football player misses just after he first miss

P (Y) = 0.2

Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:

P (E) = P (X). P (Y)

P (E) = 0.4*0.2

P (E) = 0.08