Is (x + 1) a factor of f (x) = x^3 + x^2 - 4x - 4?

Select the appropriate response:

Yes

or

No

Yes

Step-by-step explanation:

(x^3 + x^2) (-4x - 4)

x^2 (x+1) - 4 (x+1)

(x^2 - 4) (x+1)

(x-2) (x+2) (x+1)

X = 2 x=-2 x=-1

Yes

Step-by-step explanation:

f (x) = x^3 + x^2 - 4x - 4

Factor by grouping taking x^2 out of the first group and - 4 out of the second

0 = x^3 + x^2 - 4x - 4

x^2 (x+1) - 4 (x+1)

Factor out (x+1)

0 = (x+1) (x^2-4)

Now we have the difference of squares

0 = (x+1) (x-2) (x+2)

x+1 is a factor